코딩숙제 + 1 3주차 스파르타 숙제24 select e.enrolled_id, e.user_id count(*) as cnt from enrolleds e inner join enrolleds_derail ed on e.enrolled_id = ed.enrolled_id where ed.done = 1 group by e. enrolled_id, e.user_id order by cnt desc 코딩 2023.06.24 24 이전 1 다음 myoskin 티스토리툴바 라미의 방구석잡담.구독하기